What is the voltage output of a battery if a light bulb in the circuit has a resistance of 100 ohms and 1 ampere of current flows?

Study for the 3rd Class Power Engineering (3A2) Exam. Explore multiple choice questions with hints and explanations. Prepare for your certification!

To determine the voltage output of the battery based on the given resistance and current, Ohm’s Law can be applied. Ohm’s Law states that the voltage (V) across a conductor is equal to the product of the current (I) flowing through it and the resistance (R) of the conductor. The formula for Ohm’s Law is given by:

V = I × R

In this scenario, the resistance of the light bulb is 100 ohms, and the current flowing through the circuit is 1 ampere. Applying the values into the formula:

V = 1 ampere × 100 ohms = 100 volts

Thus, the voltage output of the battery is calculated to be 100 volts. This aligns with the principles of electrical circuits and Ohm's Law, confirming that the voltage is directly proportional to both current and resistance in the circuit. Understanding this relationship is essential in power engineering, especially for analyzing circuit behavior in various applications.

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