What is the resistance of a resistor that dissipates 60 watts at 110 volts?

To find the resistance of a resistor that dissipates 60 watts at 110 volts, you can use Ohm's Law and the power formula. The power (P) dissipated by a resistor is given by the formula:

P = V^2 / R

where P is the power in watts, V is the voltage in volts, and R is the resistance in ohms. Rearranging the formula to solve for resistance gives:

R = V^2 / P

Substituting the known values (V = 110 volts and P = 60 watts) into this formula:

R = (110^2) / 60

Calculating this step-by-step:

1. First, calculate 110 squared, which is 12100.

2. Then divide that by 60.

Doing the calculation gives:

R = 12100 / 60 = 201.666... ohms

This can be rounded to 201.66 ohms.

Thus, the correct response indicating the resistance of the resistor that dissipates 60 watts at 110 volts is indeed approximately 201.66 ohms.