What are the peak-to-peak and RMS values of voltage with a maximum value of 311 V?

To understand why the choice of 622 V peak-to-peak and 220 V RMS is correct given a maximum voltage of 311 V, it’s essential to understand the definitions of these electrical terms.

The peak voltage (V_max) is the maximum voltage of the waveform, which in this case is given as 311 V. The peak-to-peak voltage (V_pp) is twice the peak voltage, calculated as follows:

V_pp = 2 * V_max = 2 * 311 V = 622 V.

This means the full swing of the waveform, from its minimum to maximum, is 622 V.

Next, to find the RMS (Root Mean Square) value of an AC voltage, we use the formula for a sine wave:

V_rms = V_max / √2.

Therefore, for a maximum voltage of 311 V:

V_rms = 311 V / √2 ≈ 311 V / 1.414 ≈ 220 V.

This means that we can equivalently describe the AC voltage by saying it can produce the same power as a 220 V DC voltage.

Thus, the peak-to-peak value of 622 V and the RMS value of 220 V accurately reflect the