What are the peak-to-peak and maximum values of alternating current if the RMS current value is 20 A?

Study for the 3rd Class Power Engineering (3A2) Exam. Explore multiple choice questions with hints and explanations. Prepare for your certification!

To determine the peak and peak-to-peak values of an alternating current from the RMS (Root Mean Square) value, one can use the relationship between these values.

The RMS value is related to the maximum (or peak) value through the equation:

[ I_{max} = I_{rms} \times \sqrt{2} ]

Given an RMS current value of 20 A, we can calculate the maximum current:

[ I_{max} = 20 , A \times \sqrt{2} \approx 20 , A \times 1.414 = 28.28 , A ]

When we talk about the peak-to-peak value, it is simply twice the maximum value. Therefore:

[ I_{peak-to-peak} = 2 \times I_{max} = 2 \times 28.28 \approx 56.57 , A ]

Thus, the peak value is approximately 28.29 A, and the peak-to-peak value is approximately 56.57 A. This aligns perfectly with the provided choice, confirming that it is indeed the correct answer. Understanding these relationships allows engineers to accurately analyze and design systems involving alternating currents.

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