In an inductive single-phase circuit with a wattmeter of 2800 W and an ammeter reading of 25 A, what is the apparent power?

Study for the 3rd Class Power Engineering (3A2) Exam. Explore multiple choice questions with hints and explanations. Prepare for your certification!

To determine the apparent power in an inductive single-phase circuit, you can use the formula for apparent power, which is the product of the voltage and the current in the circuit. The relationship between real power (measured by the wattmeter), current readings from the ammeter, and apparent power can also be examined.

In this instance, the apparent power (measured in volt-amperes, VA) can also be computed from the current reading and the voltage. If the wattmeter reads 2800 W and the ammeter shows a current of 25 A, the understanding of the power factor is crucial. However, without needing to determine the power factor directly, you can calculate the apparent power by rearranging the formula:

  1. Real Power (P) is 2800 W.

  2. Current (I) is 25 A.

To derive the apparent power (S), you can represent it as follows in a single-phase circuit:

[ S = V \times I ]

But since the voltage (V) isn't given directly, you can use the relationship between real power and apparent power in terms of power factor (PF):

[ P = S \times PF ]

Since the wattmeter is measuring real power and the am

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