In a single-phase circuit with a current of 20 A and a voltage of 220 V, what is the real power if the power factor is 78.8%?

To calculate the real power in a single-phase circuit, you use the formula:

[ P = V \times I \times PF ]

where ( P ) is the real power in watts, ( V ) is the voltage in volts, ( I ) is the current in amperes, and ( PF ) is the power factor.

Given the values:

• Voltage (V) = 220 V

• Current (I) = 20 A

• Power Factor (PF) = 78.8% = 0.788 (when converted from a percentage to a decimal)

Now, substituting these values into the formula:

[ P = 220 , V \times 20 , A \times 0.788 ]

Calculating step-by-step:

1. First, multiply the voltage by the current:

[ 220 \times 20 = 4400 , VA , (volt-amperes) ]

2. Then, multiply by the power factor:

[ 4400 \times 0.788 = 3467.2 , W ]

Since we typically round to the nearest whole number in practical applications, this results in approximately 346