In a series circuit with two lamps of equal resistance, what is the resistance of each lamp if the total voltage is 220 and the current is 2.75 amps?

To determine the resistance of each lamp in a series circuit with two lamps of equal resistance, we start by applying Ohm's law, which states that voltage (V) equals current (I) multiplied by resistance (R). In a series circuit, the total resistance is the sum of the individual resistances.

Given that the total voltage across the two lamps is 220 volts and the current flowing through the circuit is 2.75 amps, we can first calculate the total resistance using Ohm's law:

Total Resistance (R_total) = Total Voltage (V_total) / Current (I)

R_total = 220 volts / 2.75 amps

R_total = 80 ohms

Since the two lamps have equal resistance, we can denote the resistance of each lamp as R. Therefore, the total resistance of the circuit can also be expressed as:

R_total = R + R = 2R

Setting this equal to the calculated total resistance, we have:

2R = 80 ohms

To find the resistance of each lamp, we divide both sides of the equation by 2:

R = 80 ohms / 2

R = 40 ohms

This shows that the resistance of each lamp is