If the electric cost is 10 cents per kWh and the resistance is 10 ohms at 110 volts for 2 hours, what is the cost?

Study for the 3rd Class Power Engineering (3A2) Exam. Explore multiple choice questions with hints and explanations. Prepare for your certification!

To determine the cost of electricity consumed, we first need to calculate the power usage in kilowatt-hours (kWh).

Using Ohm’s law, the current (I) can be calculated from the resistance (R) and voltage (V) using the formula:

[ I = \frac{V}{R} = \frac{110 \text{ volts}}{10 \text{ ohms}} = 11 \text{ amps} ]

Next, we can calculate the power (P) in watts:

[ P = V \times I = 110 \text{ volts} \times 11 \text{ amps} = 1210 \text{ watts} ]

Now, to convert watts to kilowatts:

[ P_{\text{kW}} = \frac{1210 \text{ watts}}{1000} = 1.21 \text{ kW} ]

Next, we calculate the energy consumed over 2 hours:

[ \text{Energy (kWh)} = P_{\text{kW}} \times \text{Time (hours)} = 1.21 \text{ kW} \times 2 \text{ hours} = 2.42 \text{

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