If an inductive single-phase circuit has a wattmeter reading of 2400 W and an ammeter reading of 15 A, what is the power factor?

To find the power factor of the inductive single-phase circuit, we need to understand the relationship between real power (measured in watts), apparent power (measured in volt-amperes), and power factor.

Real power (P) is noted as 2400 W (watts), and the current (I) is given as 15 A (amperes). We can calculate the apparent power (S) using the formula:

[

S = V \times I

]

However, since the voltage (V) is not provided directly, we can derive the voltage using the formula for apparent power in terms of current and power factor:

[

S = P / \text{power factor}

]

The apparent power can also be represented as:

[

S = V \times I = V \times 15 A

]

Now, we know the following:

1. Real power (P) = 2400 W

2. Apparent power (S) = V × 15 A = ( \sqrt{P^2 + Q^2} ) (where Q is reactive power, but we're primarily looking at P and voltage here).

To calculate the power factor (PF), which is defined