If a resistor has a maximum loading current of 2 amps and a power rating of 1.5 watts, what is its resistance?

Study for the 3rd Class Power Engineering (3A2) Exam. Explore multiple choice questions with hints and explanations. Prepare for your certification!

To find the resistance of the resistor, you can apply Ohm's Law and the power formula. The power rating of the resistor is given by the equation:

[ P = I^2 R ]

Where:

  • ( P ) is the power (1.5 watts),

  • ( I ) is the current (2 amps),

  • ( R ) is the resistance in ohms.

Rearranging this formula to solve for resistance gives:

[ R = \frac{P}{I^2} ]

Substituting the values provided:

[ R = \frac{1.5}{(2)^2} = \frac{1.5}{4} = 0.375 \text{ ohms} ]

To convert ohms to milliohms, multiply by 1000:

[ 0.375 \text{ ohms} = 375 \text{ milliohms} ]

This calculation demonstrates that the correct resistance is indeed 375 milliohms, confirming the provided answer. Understanding how to apply Ohm's Law and the power formulas in electrical engineering is crucial, especially when determining specifications for components in electrical circuits.

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