A solenoid has a frequency of 60 Hz and an inductance of 0.6 H. What is the current flowing through the solenoid when supplied at 110 V?

To determine the current flowing through the solenoid when supplied at 110 V, we can use the formula for the reactance of an inductor and Ohm's law.

The inductive reactance (X_L) of the solenoid can be calculated using the formula:

[ X_L = 2 \pi f L ]

where:

• ( f ) is the frequency in hertz (Hz),

• ( L ) is the inductance in henries (H).

For this solenoid:

• ( f = 60 \text{ Hz} )

• ( L = 0.6 \text{ H} )

Substituting the values:

[ X_L = 2 \pi (60) (0.6) ]

[ X_L = 2 \pi \cdot 36 ]

[ X_L = 226.19 \text{ ohms (approximately)} ]

Now that we have the inductive reactance, we can calculate the current using Ohm's law:

[ I = \frac{V}{X_L} ]

where:

• ( I ) is the current in amps,

• ( V ) is the voltage in volts.

Substituting the